What is the compound amount on Rs. 10,000 at 10% per annum for 2 years?
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Compound amount is P(1 + r)².
Thus, 10,000 × 1.1² = Rs. 12,100.
Practice GAT Quantitative Reasoning questions with answers and explanations.
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Compound amount is P(1 + r)².
Thus, 10,000 × 1.1² = Rs. 12,100.
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Five parts equal Rs. 50,000, so one part is Rs. 10,000.
Expenditure is four parts, leaving one part as saving.
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The amount is 8,000 × 1.05² = Rs. 8,820.
Subtracting the principal gives compound interest of Rs. 820.
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Six consecutive integers centered at 17.5 are 15 through 20.
Therefore, the smallest is 15.
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
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The average of 1 through n is (n + 1)/2.
Setting (n + 1)/2 = 20 gives n = 39.
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Doubling means interest equal to the principal is earned in 8 years.
Tripling requires interest equal to twice the principal, so it takes 16 years.
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The difference between C and A is 2 ratio parts, equal to Rs. 600.
One part is Rs. 300, so 12 parts total Rs. 3,600.
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Initially, milk is 42 liters and water is 18 liters.
For a 7:5 ratio with 42 liters milk, water must be 30 liters, so add 12.
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Let the numbers be 5k and 8k; then (5k + 9)/(8k + 9) = 2/3.
Solving gives k = 9, so the smaller number is 45.
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Profit equals selling price minus cost price.
Thus, 920 - 800 = Rs. 120.
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The weighted sum is 70 × 2 + 90 × 3 = 410.
Dividing by the total weight 5 gives 82.