Practice GAT Quantitative Reasoning questions with answers and explanations.
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A 10% loss on Rs. 1,200 is Rs. 120.
Subtracting gives a selling price of Rs. 1,080.
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The total score is 20 × 60 + 30 × 70 = 3,300.
Dividing by 50 students gives 66.
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The selling price is 125% of the cost price.
Thus, cost price = 1,500 ÷ 1.25 = Rs. 1,200.
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The total ratio parts are 7, so one part is 35/7 = 5 liters.
Water is two parts, or 10 liters.
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The discount is 15% of Rs. 2,000, which is Rs. 300.
The sale price is Rs. 2,000 - Rs. 300 = Rs. 1,700.
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Thirty percent of 20 liters is 0.30 × 20.
This equals 6 liters.
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After a 10% discount, 90% remains; after another 20%, 80% of that remains.
The final price is 72%, so the total discount is 28%.
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The solution contains 4 liters of salt, which remains unchanged.
For salt to be 25%, total volume must be 16 liters, so 6 liters are added.
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Let cost be 100; marked price is 125 and sale price is 90% of 125 = 112.5.
The profit is 12.5 on a cost of 100.
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For direct variation, x/y is constant.
The constant is 18/6 = 3, so x = 3 × 10 = 30.
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Simple interest is PRT/100.
So 5,000 × 8 × 3 ÷ 100 = Rs. 1,200.
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The greatest common divisor of 24 and 36 is 12.
Dividing both terms by 12 gives 2:3.
