Practice GAT Subject Statistics questions with answers and explanations.
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Not green means drawing one of the six yellow balls.
The probability is 6/10 = 3/5.
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An event and its complement sum to one.
P(Aᶜ) = 1 - 0.35 = 0.65.
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Mutually exclusive events have no overlap.
P(A ∪ B) = 0.30 + 0.25 = 0.55.
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Apply inclusion-exclusion for the union.
0.6 + 0.5 - 0.3 = 0.8.
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For independent events, multiply their probabilities.
P(A ∩ B) = 0.4 × 0.5 = 0.2.
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Conditional probability is P(A ∩ B) divided by P(B).
0.18 ÷ 0.30 = 0.6.
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The four equally likely outcomes are HH, HT, TH, and TT.
Only HH has two heads, giving probability 1/4.
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Use the complement of getting no heads.
P(at least one head) = 1 - P(TT) = 1 - 1/4 = 3/4.
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The even outcomes are 2, 4, and 6 out of six equally likely outcomes.
Thus the probability is 3/6 = 1/2.
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The favorable outcomes are 5 and 6.
Therefore the probability is 2/6 = 1/3.
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Six ordered pairs sum to 7 out of 36 equally likely pairs.
The probability is 6/36 = 1/6.
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There are four aces among 52 cards.
The probability is 4/52 = 1/13.
