GATE ME NAT 25: A 3 kg body moves at 8 m/s. Enter kinetic energy in joules.
Correct Answer: 96
Explanation:
KE=½mv²=96.0 J.
MCQ Collection
GATE ME NAT MCQs
Practice GATE ME NAT questions with answers and explanations.
GATE ME NAT 26: A heat engine receives 160 kJ and rejects 40 kJ. Enter efficiency as a percentage.
Correct Answer: 75
Explanation:
η=(Qin−Qout)/Qin=75.0%.
GATE ME NAT 27: A constant force of 5 N moves a body 7 m in its direction. Enter work in joules.
Correct Answer: 35
Explanation:
W=Fd=35 J.
GATE ME NAT 28: A 6 kg body moves at 3 m/s. Enter kinetic energy in joules.
Correct Answer: 27
Explanation:
KE=½mv²=27.0 J.
GATE ME NAT 29: A heat engine receives 420 kJ and rejects 60 kJ. Enter efficiency as a percentage.
Correct Answer: 85.71
Explanation:
η=(Qin−Qout)/Qin=85.71%.
GATE ME NAT 30: A constant force of 8 N moves a body 9 m in its direction. Enter work in joules.
Correct Answer: 72
Explanation:
W=Fd=72 J.
GATE ME NAT 16: A 2 kg body moves at 9 m/s. Enter kinetic energy in joules.
Correct Answer: 81
Explanation:
KE=½mv²=81.0 J.
GATE ME NAT 17: A heat engine receives 150 kJ and rejects 50 kJ. Enter efficiency as a percentage.
Correct Answer: 66.67
Explanation:
η=(Qin−Qout)/Qin=66.67%.
GATE ME NAT 18: A constant force of 4 N moves a body 8 m in its direction. Enter work in joules.
Correct Answer: 32
Explanation:
W=Fd=32 J.
GATE ME NAT 19: A 5 kg body moves at 4 m/s. Enter kinetic energy in joules.
Correct Answer: 40
Explanation:
KE=½mv²=40.0 J.
GATE ME NAT 20: A heat engine receives 420 kJ and rejects 70 kJ. Enter efficiency as a percentage.
Correct Answer: 83.33
Explanation:
η=(Qin−Qout)/Qin=83.33%.
GATE ME NAT 21: A constant force of 7 N moves a body 3 m in its direction. Enter work in joules.
Correct Answer: 21
Explanation:
W=Fd=21 J.