JEE Advanced Paper 1 Chemistry numerical 2115: Evaluate 24(4+1).
Correct Answer: 120
Explanation:
24×5=120.
MCQ Collection
JEE Advanced Chemistry Numerical MCQs
Practice JEE Advanced Chemistry Numerical questions with answers and explanations.
JEE Advanced Paper 1 Chemistry numerical 2116: If the roots of z²−11z+18=0 are r and s, enter r+s.
Correct Answer: 11
Explanation:
Vieta gives r+s=11.
JEE Advanced Paper 1 Chemistry numerical 2117: Enter the positive value of |3²−14|.
Correct Answer: 193
Explanation:
193
JEE Advanced Paper 1 Chemistry numerical 2118: Enter the area of a triangle with base 4 and height 19.
Correct Answer: 38
Explanation:
Area=½×4×19=38.0.
JEE Advanced Paper 1 Chemistry numerical 2119: A sequence starts at 12 and each term is three times the preceding term. Enter the second term.
Correct Answer: 36
Explanation:
36
JEE Advanced Paper 1 Chemistry numerical 2110: Evaluate 19(13+1).
Correct Answer: 266
Explanation:
19×14=266.
JEE Advanced Paper 1 Chemistry numerical 2111: If the roots of z²−38z+360=0 are r and s, enter r+s.
Correct Answer: 38
Explanation:
Vieta gives r+s=38.
JEE Advanced Paper 1 Chemistry numerical 2112: Enter the positive value of |21²−6|.
Correct Answer: 435
Explanation:
435