JEE Advanced Paper 2 Chemistry numerical 4115: Evaluate 23(8+1).
Correct Answer: 207
Explanation:
23×9=207.
MCQ Collection
JEE Advanced Chemistry Numerical MCQs
Practice JEE Advanced Chemistry Numerical questions with answers and explanations.
JEE Advanced Paper 2 Chemistry numerical 4116: If the roots of z²−37z+312=0 are r and s, enter r+s.
Correct Answer: 37
Explanation:
Vieta gives r+s=37.
JEE Advanced Paper 2 Chemistry numerical 4117: Enter the positive value of |2²−18|.
Correct Answer: 322
Explanation:
322
JEE Advanced Paper 2 Chemistry numerical 4118: Enter the area of a triangle with base 3 and height 6.
Correct Answer: 9
Explanation:
Area=½×3×6=9.0.
JEE Advanced Paper 2 Chemistry numerical 4119: A sequence starts at 15 and each term is three times the preceding term. Enter the second term.
Correct Answer: 45
Explanation:
45
JEE Advanced Paper 2 Chemistry numerical 4111: If the roots of z²−24z+95=0 are r and s, enter r+s.
Correct Answer: 24
Explanation:
Vieta gives r+s=24.
JEE Advanced Paper 2 Chemistry numerical 4112: Enter the positive value of |20²−10|.
Correct Answer: 390
Explanation:
390
JEE Advanced Paper 2 Chemistry numerical 4113: Enter the area of a triangle with base 21 and height 15.
Correct Answer: 157.5
Explanation:
Area=½×21×15=157.5.
JEE Advanced Paper 2 Chemistry numerical 4114: A sequence starts at 25 and each term is three times the preceding term. Enter the second term.
Correct Answer: 75
Explanation:
75
JEE Advanced Paper 2 Chemistry numerical 4110: Evaluate 18(17+1).
Correct Answer: 324
Explanation:
18×18=324.
JEE Advanced Paper 1 Chemistry numerical 2113: Enter the area of a triangle with base 22 and height 11.
Correct Answer: 121
Explanation:
Area=½×22×11=121.0.
JEE Advanced Paper 1 Chemistry numerical 2114: A sequence starts at 39 and each term is three times the preceding term. Enter the second term.
Correct Answer: 117
Explanation:
117