Senior-secondary mathematics task 107: What is the area of a circle of radius 3?
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Use the circle-area formula A = πr². Substituting r = 3 gives A = π × 3² = 9π.
Algebra, arithmetic, reasoning.
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Use the circle-area formula A = πr². Substituting r = 3 gives A = π × 3² = 9π.
Percentage=(14/29)×100=48.28.
Subtract 4 from both sides and divide by 5: x = (59-4)/5 = 11.
By Vieta’s formula, the sum of the roots equals the coefficient 9.
aₙ=a₁+(n−1)d=3+(15−1)×5=73.
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The sum is n(n+1)/2=28, so the mean is 28/7.
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There are 2 favourable outcomes out of 9 equally likely outcomes, so P(red)=2/9.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
An antiderivative is 2/2 x²+5x. At x=3, the value is 24.0.
The dot product is 2×2+6×4=28.
Rewrite the value using base 3: 27 = 3^3. Matching exponents gives x = 3.
aₙ=a₁+(n−1)d=2+(14−1)×4=54.