Algebra, arithmetic, reasoning.
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The sum is n(n+1)/2=21, so the mean is 21/6.
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There are 6 favourable outcomes out of 12 equally likely outcomes, so P(red)=6/12.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=15x²+8x. Substituting x=2 gives 76.
Percentage=(13/28)×100=46.43.
Subtract 3 from both sides and divide by 4: x = (43-3)/4 = 10.
By Vieta’s formula, the sum of the roots equals the coefficient 6.
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The sum is n(n+1)/2=15, so the mean is 15/5.
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There are 5 favourable outcomes out of 10 equally likely outcomes, so P(red)=5/10.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=12x²+6x. Substituting x=1 gives 18.
An antiderivative is 1/2 x²+4x. At x=2, the value is 10.0.
