MDCAT Chemistry MCQs

Volume at STP = moles × 22.4 L mol⁻¹.
The calculated volume is 44.8 L.

Volume at STP = moles × 22.4 L mol⁻¹.
The calculated volume is 67.2 L.

Kc contains product concentrations over reactant concentrations.
Each concentration is raised to its stoichiometric coefficient.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 3×400÷300 = 4 L.

Kc contains product concentrations over reactant concentrations.
Each concentration is raised to its stoichiometric coefficient.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 5×300÷250 = 6 L.

Kc contains product concentrations over reactant concentrations.
Each concentration is raised to its stoichiometric coefficient.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 2×500÷200 = 5 L.

Kc contains product concentrations over reactant concentrations.
Each concentration is raised to its stoichiometric coefficient.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 4×400÷320 = 5 L.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 6×300÷360 = 5 L.

PV = nRT, so P = nRT/V.
Substitution gives approximately 100 kPa.