An ideal gas has n = 2 mol, T = 300 K and V = 0.0499 m³. Using R = 8.31 J mol⁻¹ K⁻¹, what is its pressure?
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PV = nRT, so P = nRT/V.
Substitution gives approximately 99.9 kPa.
Practice MDCAT Chemistry questions with answers and explanations.
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PV = nRT, so P = nRT/V.
Substitution gives approximately 99.9 kPa.
Choose an option to check your answer.
PV = nRT, so P = nRT/V.
Substitution gives approximately 100 kPa.
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Percentage yield = actual yield ÷ theoretical yield × 100.
(45 ÷ 50) × 100 = 90%.
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Boyle’s law gives P₁V₁ = P₂V₂.
P₂ = 100×4÷2 = 200 kPa.
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Boyle’s law gives P₁V₁ = P₂V₂.
P₂ = 120×3÷6 = 60 kPa.
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Boyle’s law gives P₁V₁ = P₂V₂.
P₂ = 80×5÷4 = 100 kPa.
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Boyle’s law gives P₁V₁ = P₂V₂.
P₂ = 150×2÷5 = 60 kPa.
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Boyle’s law gives P₁V₁ = P₂V₂.
P₂ = 90×6÷3 = 180 kPa.
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Percentage yield = actual yield ÷ theoretical yield × 100.
(72 ÷ 80) × 100 = 90%.
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Percentage yield = actual yield ÷ theoretical yield × 100.
(15 ÷ 20) × 100 = 75%.
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The balanced equation fixes the required mole ratio.
Comparison of available amounts shows that O₂ is consumed first.
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The balanced equation fixes the required mole ratio.
Comparison of available amounts shows that N₂ is consumed first.