A 2 kg body changes velocity from 6 m/s to -3 m/s. What impulse acts on it?
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Impulse equals change in momentum, J = m(v−u).
The sign indicates direction relative to the chosen positive axis.
Practice MDCAT Physics questions with answers and explanations.
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Impulse equals change in momentum, J = m(v−u).
The sign indicates direction relative to the chosen positive axis.
Choose an option to check your answer.
Conservation of mass for steady incompressible flow gives A₁v₁=A₂v₂.
Solving gives the stated speed.
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Impulse equals change in momentum, J = m(v−u).
The sign indicates direction relative to the chosen positive axis.
Choose an option to check your answer.
For a perfectly elastic one-dimensional collision, relative speed of approach equals relative speed of separation.
The comparison determines the classification.
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For a perfectly elastic one-dimensional collision, relative speed of approach equals relative speed of separation.
The comparison determines the classification.
Choose an option to check your answer.
For a perfectly elastic one-dimensional collision, relative speed of approach equals relative speed of separation.
The comparison determines the classification.
Choose an option to check your answer.
For a perfectly elastic one-dimensional collision, relative speed of approach equals relative speed of separation.
The comparison determines the classification.
Choose an option to check your answer.
Work is the scalar product W = Fd cosθ.
The angle determines the effective force component.
Choose an option to check your answer.
Work is the scalar product W = Fd cosθ.
The angle determines the effective force component.
Choose an option to check your answer.
Work is the scalar product W = Fd cosθ.
The angle determines the effective force component.
Choose an option to check your answer.
Work is the scalar product W = Fd cosθ.
The angle determines the effective force component.
Choose an option to check your answer.
Work is the scalar product W = Fd cosθ.
The angle determines the effective force component.