A projectile is launched from level ground at 30 m/s and 30°. Using g = 10 m/s², what maximum height does it reach?
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Maximum height is H = u²sin²θ/(2g).
Substitution gives the stated value.
Practice MDCAT Physics questions with answers and explanations.
Choose an option to check your answer.
Maximum height is H = u²sin²θ/(2g).
Substitution gives the stated value.
Choose an option to check your answer.
Range is R = u²sin2θ/g for equal launch and landing heights.
Substitution gives the stated value.
Choose an option to check your answer.
Time of flight is T = 2u sinθ/g.
Substitution gives the stated value.
Choose an option to check your answer.
Maximum height is H = u²sin²θ/(2g).
Substitution gives the stated value.
Choose an option to check your answer.
Range is R = u²sin2θ/g for equal launch and landing heights.
Substitution gives the stated value.
Choose an option to check your answer.
Time of flight is T = 2u sinθ/g.
Substitution gives the stated value.
Choose an option to check your answer.
Maximum height is H = u²sin²θ/(2g).
Substitution gives the stated value.
Choose an option to check your answer.
Range is R = u²sin2θ/g for equal launch and landing heights.
Substitution gives the stated value.
Choose an option to check your answer.
Total momentum before equals total momentum after.
For sticking bodies, v = (m₁u₁+m₂u₂)/(m₁+m₂).
Choose an option to check your answer.
Range is R = u²sin2θ/g for equal launch and landing heights.
Substitution gives the stated value.
Choose an option to check your answer.
Time of flight is T = 2u sinθ/g.
Substitution gives the stated value.
Choose an option to check your answer.
Maximum height is H = u²sin²θ/(2g).
Substitution gives the stated value.