MCQ Collection
NAT Chemistry MCQs
Practice NAT Chemistry questions with answers and explanations.
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Correct Answer: D. An atom or group with a net electric charge
Explanation:
Ions form by gaining or losing electrons.
Cations are positive and anions are negative.
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Correct Answer: D. Energy required to remove an electron from a gaseous atom or ion
Explanation:
First ionization energy removes the first electron from a neutral gaseous atom.
Successive ionization energies remove additional electrons.
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Correct Answer: A. A positively charged ion
Explanation:
A cation forms when electrons are lost.
It has more protons than electrons.
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Correct Answer: A. Energy change when a gaseous atom gains an electron
Explanation:
Electron affinity reflects attraction for an added electron.
Its sign and magnitude vary across the periodic table.
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Correct Answer: B. A negatively charged ion
Explanation:
An anion forms when electrons are gained.
It has more electrons than protons.
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Correct Answer: B. Ability of a bonded atom to attract shared electrons
Explanation:
Electronegativity helps predict bond polarity.
Fluorine has the highest common electronegativity.
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Correct Answer: C. Ernest Rutherford
Explanation:
Rutherford concluded that atoms contain a small dense positive nucleus.
Most atomic volume is empty space.
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Correct Answer: C. Electrons in the outermost occupied shell involved in bonding
Explanation:
Valence electrons largely determine chemical reactivity.
Elements in a group often share similar valence configurations.
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Correct Answer: A. Number of protons in its nucleus
Explanation:
Atomic number identifies the element.
In a neutral atom it also equals the number of electrons.
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Correct Answer: B. Total number of protons and neutrons
Explanation:
Mass number applies to a specific isotope.
It is always a whole number.
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Correct Answer: D. 117 g
Explanation:
Mass equals moles multiplied by molar mass.
2×58.5 = 117 g.
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Correct Answer: A. 3.011 × 10^23
Explanation:
Particles equal moles times Avogadro's number.
0.5×6.022×10^23 = 3.011×10^23 molecules.