A 15 kg box is pulled right by 80 N and left by 20 N. What is its acceleration?
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The net force is 80-20 = 60 N.
Acceleration is 60/15 = 4 m/s².
Practice GAT Subject Physics questions with answers and explanations.
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The net force is 80-20 = 60 N.
Acceleration is 60/15 = 4 m/s².
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Constant velocity means zero acceleration and zero net force.
The normal force therefore equals the person's weight, 600 N.
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Weight is W=mg.
W=7×10 = 70 N.
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Vertical equilibrium requires normal force to balance weight.
N=mg=10×10 = 100 N.
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Opposing forces subtract.
Net force = 50-20 = 30 N.
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Use a=F/m.
A=12/4 = 3 m/s².
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Centripetal force is mv²/r.
F=2×36/4 = 18 N.
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Centripetal acceleration is v²/r.
A=100/20 = 5 m/s².
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Acceleration is F/m = 4 m/s².
Change in velocity is at=4×3 = 12 m/s.
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Use s=ut+½at² with u=0.
S=½×2×25 = 25 m.
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Use s=ut+½at².
S=10×5+½×2×25 = 50+25 = 75 m.
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Use v²=u²+2as.
100-16 = 42a, so a=2 m/s².