NAT MCQs

Stoichiometry uses balanced equations to relate amounts.
It supports mass, mole, particle, and gas calculations.

Moles equal mass divided by molar mass.
18 g ÷ 18 g/mol = 1 mol.

Mass equals moles multiplied by molar mass.
2×58.5 = 117 g.

Particles equal moles times Avogadro's number.
0.5×6.022×10^23 = 3.011×10^23 molecules.

Moles equal particles divided by Avogadro's number.
1.2044×10^24 ÷ 6.022×10^23 = 2 mol.

An element cannot be broken down chemically into simpler substances.
Each element is identified by its atomic number.

An excess reactant is supplied beyond the stoichiometric requirement.
Some remains when the reaction is complete.

Compounds have definite formulas and characteristic properties.
Their components can be separated only by chemical means.

Theoretical yield assumes complete reaction and no losses.
It is calculated from the limiting reactant.

Mixture components retain much of their individual identity.
They can often be separated by physical methods.

Actual yield is measured after the experiment.
It is usually lower than theoretical yield.

Solutions are homogeneous mixtures.
Any sampled portion has approximately the same composition.